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11x^2-20x+9=0
a = 11; b = -20; c = +9;
Δ = b2-4ac
Δ = -202-4·11·9
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-2}{2*11}=\frac{18}{22} =9/11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+2}{2*11}=\frac{22}{22} =1 $
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